Question: 1 -
Find the Compound Interest on Rs. 1000 for two years at 2% per annum.
-
20.5
-
20.6
-
20
-
20.4
Answer:
20.4
Solution:
Principal for the first year = Rs. 1000
Interest for the first year = 1000 × 2 × 1/100 = Rs. 20
Amount at the end of one year = 1000 + 20 = Rs. 1020
Interest for second year = 1020 × 2 × 1/100 = Rs. 20.4
Principal for the second year = Rs. 1020
Amount at the end of one year = 1000 + 20. 4 = Rs. 1040.4
C.I. = Amount – Principal = 1040.4 – 1020 = Rs. 20.4.
Principal for the first year = Rs. 1000
Interest for the first year = 1000 × 2 × 1/100 = Rs. 20
Amount at the end of one year = 1000 + 20 = Rs. 1020
Interest for second year = 1020 × 2 × 1/100 = Rs. 20.4
Principal for the second year = Rs. 1020
Amount at the end of one year = 1000 + 20. 4 = Rs. 1040.4
C.I. = Amount – Principal = 1040.4 – 1020 = Rs. 20.4.
Question: 2 -
Calculate the compound interest at the rate of 6% per annum for 2 years on the principle which in 2 years at the rate of 2% per annum gives Rs. 8000 as simple interest.
-
59440
-
49000
-
49440
-
50000
Answer:
49440
Solution:
P = 8000 × 100/2 × 2 = 400000
A = 400000(1 + 6/100)2 = 400000 (53/50)2 = Rs. 449440
C.I. = 449440 – 400000 = Rs. 49440.
P = 8000 × 100/2 × 2 = 400000
A = 400000(1 + 6/100)2 = 400000 (53/50)2 = Rs. 449440
C.I. = 449440 – 400000 = Rs. 49440.
Question: 3 -
Vidhya lent Rs. 5000 to Kavya for 3 years at the rate of 5% per annum compound interest. Calculate the amount that Vidhya will get after 3 years.
-
5788
-
5788.13
-
5789
-
5788.12
Answer:
5788.13
Solution:
A = P (1 + R/100)n
Amount for 3 years = 5000 (1 + 5/100)3 = 5000 (21/20)3 = 5788.13.
A = P (1 + R/100)n
Amount for 3 years = 5000 (1 + 5/100)3 = 5000 (21/20)3 = 5788.13.
Question: 4 -
A farmer gets a loan of Rs. 100000 against his fixed deposits. If the rate of interest is 1.5 paise per rupee per annum, calculate the compound interest payable after 2 years.
-
52250
-
32250
-
42250
-
22250
Answer:
32250
Solution:
R = 1.5 paise per rupee per annum = 1.5 × 100 paise per hundred rupee per annum
= 1.5 × 100/100 rupee per hundred rupee per annum = 1.5%
Amount = 100000 (1 + 1.5/100)2 = 100000 (23/20)2 = 132250
C.I. = 132250 – 100000 = Rs. 32250.
R = 1.5 paise per rupee per annum = 1.5 × 100 paise per hundred rupee per annum
= 1.5 × 100/100 rupee per hundred rupee per annum = 1.5%
Amount = 100000 (1 + 1.5/100)2 = 100000 (23/20)2 = 132250
C.I. = 132250 – 100000 = Rs. 32250.
Question: 5 -
Evaluate the compound interest on Rs. 10101 for 3 years at the rate of 9% per annum compounded annually.
-
2980
-
10101
-
30000
-
33333
Answer:
2980
Solution:
A = P (1 + R/100)n
⇒ A = 10101 (1 + 9/100)3 = 10101 (109/100)3 = Rs. 13081.08
C.I. = A – P = 13081.08 – 10101 = Rs. 2980.08.
A = P (1 + R/100)n
⇒ A = 10101 (1 + 9/100)3 = 10101 (109/100)3 = Rs. 13081.08
C.I. = A – P = 13081.08 – 10101 = Rs. 2980.08.